...集合中添加新元素,如果该元素已存在则不做任何改变 s1 = {1,2,3} s1.add(qwe) print(s1) ---------- {1, 2, 3, qwe} update(*others)可将其他可迭代对象(比如字符串、列表、元组)添加到集合中,自动删除重复元素 s1 = {1,2,3} it = [3,4,5] s1.update...
集合,不可重复的列表,可变类型 difference s1中存在,s2中不存在 s1 = {xmzncc,fcc} s2 = {alex,wusir} v = s1.difference(s2) print(v) s2中存在,s1中不存在 s1 = {xmzncc,fcc,test} s2 = {alex,wusir,xmzncc} v = s2.difference(s1) print(v) d...
... class TestString { 2 public static void main(String[] args) { 3 String s1 = Monday; 4 String s2 = Monday; 5 if (s1 == s2) 6 { 7 System.out.println(s1 == s2);} 8 else{ 9 System.out.println...
...合中的元素不可重复,这就类似于dict键。 创建集合 >>> s1 = set(qiswri) #有两个i >>> s1 set([q, i, s, r, w]) #只有一个i >>> >>> s2 = set([123,google,facebook,book,facebook]); >>> s2 set([facebook, 123, google, book]) #只有一个faceb...
...blic class A { public static void main(String args[]) { String s1 = Hello; String s2 = Hello; System.out.println(s1 == s2); } } 肯定很多人说,输出true,确实是输出true,s1和s2引用的是同...
... public class TestString { public static void main(String[] args) { String s1 = Monday; String s2 = Monday; } } 上面这段程序中,到底有几个对象呢? 来检测一下吧,稍微改动一下程序 public class TestString { public stati...
...方法 5_String类的常见面试题* 1.判断定义为String类型的s1和s2是否相等 String s1 = abc; String s2 = abc; System.out.println(s1 == s2); //true 两个常量指向同一个地址值 System.out.println(s1.equals(s2)); //true 2.下面这句话在内存中创建...
...nitialize your data structure here. */ var MinStack = function() { this.s1 = []; this.s2 = []; }; /** * @param {number} x * @return {void} */ MinStack.prototype.push = function(x) { let...
... void main(String[] args) throws InterruptedException { String s1 = new String(vv); String s2 = vv; System.out.println(s1 == s2);//false } } 然后用...
...起组成新的集合并返回。它不改变原来的集合。 In [51]: s1, s2, s3 = {1,2,3}, {4,5,6}, {6,7,8} In [52]: s1.union(s2) Out[52]: {1, 2, 3, 4, 5, 6} In [53]: s1 Out[53]: {1, 2, 3} In [54]: s1.union(s2, s3) Out[54]: {1, 2, 3...
Problem Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = great: great / gr ...
...的; s={1,1,2,3,4,2,2} print(s) {1, 2, 3, 4} 如何定义一个空集合? s1 = {} # 默认情况是dict, 称为字典 print(s1,type(s1)) {} 定义一个空集合 s2 = set([]) print(s2,type(s2)) set() 集合应用 列表去重 lee =[1,1,23,45,565,4,32,12,23,1] ...
...Person() // 子类型的原型为父类型的一个实例对象 var s1 = new Student(15000) var s2 = new Student(14000) console.log(s1,s2) 但这种方式实现的本质是通过将子类的原型指向了父类的实例,所以子类的实例就可以通过__proto__访问到 S...
ChatGPT和Sora等AI大模型应用,将AI大模型和算力需求的热度不断带上新的台阶。哪里可以获得...
大模型的训练用4090是不合适的,但推理(inference/serving)用4090不能说合适,...
图示为GPU性能排行榜,我们可以看到所有GPU的原始相关性能图表。同时根据训练、推理能力由高到低做了...