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  • Walls and Gates

    ....com/a/11... public class Solution { public void wallsAndGates(int[][] rooms) { /* bfs for each gates, room[i][j] = distance from (i, j) to gate * update room[i][j] each time ...

    CKJOKER 评论0 收藏0
  • [Leetcode] Walls and Gates 墙与门

    ...。 代码 public class Solution { public void wallsAndGates(int[][] rooms) { if(rooms.length == 0) return; for(int i = 0; i < rooms.length; i++){ for(int j = 0; j < rooms...

    Edison 评论0 收藏0
  • Meeting Rooms & Meeting Rooms II

    Meeting Rooms Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. 思路这道题就是要找区间之间是否有overlap。对一个区间...

    TalkingData 评论0 收藏0
  • 基于express和socket.io的简易版聊天室

    ... } users.append(li) } }) // 刷新房间列表 socket.on(refresh rooms, function ({rooms, active}) { roomsList.empty(); for (let room of Object.keys(rooms)) { let li_room = $(``); let span...

    dendoink 评论0 收藏0
  • 286. Walls and Gates

    ...达的最短距离。用BFS逐层扫。 public void wallsAndGates(int[][] rooms) { if (rooms == null || rooms.length == 0 || rooms[0].length == 0) return; Queue q = new LinkedList(); int m = rooms.length, n = ...

    megatron 评论0 收藏0
  • 合成特征和离群值(接上篇的补充)

    ...此次并不是使用多个特征,而是创建一个合成特诊 total_rooms 和 population 特征都会统计指定街区的相关总计数据。但是,如果一个街区比另一个街区的人口更密集,会怎么样?我们可以创建一个合成特征(即 total_rooms 与 population ...

    XUI 评论0 收藏0
  • [Leetcode] Meeting Rooms 会议室

    Meeting Rooms Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. For example, Given [[0, 30],...

    jubincn 评论0 收藏0
  • [LeetCode] 253. Meeting Rooms II

    ...mes [[s1,e1],[s2,e2],...] (si < ei), find the minimum number of conference rooms required. Example 1: Input: [[0, 30],[5, 10],[15, 20]]Output: 2Example 2: Input: [[7,10],[2,4]]Output: 1 Solution Us...

    mengera88 评论0 收藏0
  • [LintCode/LeetCode] Meeting Rooms

    Problem Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. Example Given intervals = [[0,30],[...

    Noodles 评论0 收藏0
  • vue2.0开发聊天程序(六) 服务端的webScoket

    ... io.sockets.connected[socket.id].emit(err,user is exist); socket.rooms: 遗传哈希字符串,用来标志当前客户端所在的房间号,通过房间名称建立索引。有了房间机制就可实现给同一组房间内的socket推送消息,(可用来实现群聊) io.on(conne...

    hiyayiji 评论0 收藏0
  • 174. Dungeon Game

    ...her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must fight his way t...

    wanglu1209 评论0 收藏0
  • [Leetcode] Dungeon Game 地牢游戏

    ...her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must fight his way t...

    taoszu 评论0 收藏0
  • 使用WebRTC搭建前端视频聊天室——信令篇

    ...变成这样: var server = new WebSocketServer(); var sockets = []; var rooms = {}; /* join信令所接收的格式 { eventName: join, data: { room: roomName } } */ var joinRoom = function(data, sock...

    sixgo 评论0 收藏0

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