....com/a/11... public class Solution { public void wallsAndGates(int[][] rooms) { /* bfs for each gates, room[i][j] = distance from (i, j) to gate * update room[i][j] each time ...
...。 代码 public class Solution { public void wallsAndGates(int[][] rooms) { if(rooms.length == 0) return; for(int i = 0; i < rooms.length; i++){ for(int j = 0; j < rooms...
Meeting Rooms Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. 思路这道题就是要找区间之间是否有overlap。对一个区间...
... } users.append(li) } }) // 刷新房间列表 socket.on(refresh rooms, function ({rooms, active}) { roomsList.empty(); for (let room of Object.keys(rooms)) { let li_room = $(``); let span...
...达的最短距离。用BFS逐层扫。 public void wallsAndGates(int[][] rooms) { if (rooms == null || rooms.length == 0 || rooms[0].length == 0) return; Queue q = new LinkedList(); int m = rooms.length, n = ...
...此次并不是使用多个特征,而是创建一个合成特诊 total_rooms 和 population 特征都会统计指定街区的相关总计数据。但是,如果一个街区比另一个街区的人口更密集,会怎么样?我们可以创建一个合成特征(即 total_rooms 与 population ...
Meeting Rooms Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. For example, Given [[0, 30],...
...mes [[s1,e1],[s2,e2],...] (si < ei), find the minimum number of conference rooms required. Example 1: Input: [[0, 30],[5, 10],[15, 20]]Output: 2Example 2: Input: [[7,10],[2,4]]Output: 1 Solution Us...
Problem Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. Example Given intervals = [[0,30],[...
... io.sockets.connected[socket.id].emit(err,user is exist); socket.rooms: 遗传哈希字符串,用来标志当前客户端所在的房间号,通过房间名称建立索引。有了房间机制就可实现给同一组房间内的socket推送消息,(可用来实现群聊) io.on(conne...
...her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must fight his way t...
...her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must fight his way t...
...变成这样: var server = new WebSocketServer(); var sockets = []; var rooms = {}; /* join信令所接收的格式 { eventName: join, data: { room: roomName } } */ var joinRoom = function(data, sock...
ChatGPT和Sora等AI大模型应用,将AI大模型和算力需求的热度不断带上新的台阶。哪里可以获得...
大模型的训练用4090是不合适的,但推理(inference/serving)用4090不能说合适,...
图示为GPU性能排行榜,我们可以看到所有GPU的原始相关性能图表。同时根据训练、推理能力由高到低做了...