...aracter 统计data[i]后8位里面,从前开始有多少个1,用变量ones来保存,其中ones可能的值只有0, 2, 3, 4 从 data[i+1] 开始检查,后八位中的前两位是否为10,一共检查ones - 1 更新i的值为 i + ones public class Solution { public boolean validUtf8(...
...(HKEY_CURRENT_USERSoftwareMicrosoftWindowsCurrentVersionInternet Settingsones11001,0,REG_DWORD); WshShell.RegWrite(HKEY_CURRENT_USERSoftwareMicrosoftWindowsCurrentVersionInternet Setting...
... One-pass, constant extra space. Note 假设数a第一次出现,只存在ones里,第二次出现,从ones里消去,然后存在twos里,第三次出现,由于ones不存取已经在twos里的数,就只从twos里消去。整个过程相当于,直接在ones和twos里去掉既是ones又是...
Ones and Zeroes 题目链接:https://leetcode.com/problems... knapsack problem,这里是最基本的01背包,把cost变成了二维的。参考背包九讲:http://love-oriented.com/pack... public class Solution { public int findMaxForm(String[] strs,...
...章地址 第一题 What is the result of this expression? (or multiple ones) [1, 2, 3].map(parseInt) A:[1, 2, 3] B:[1, 2, 3] C:[0, 1, 2] D:other 解答:这里考的是map、parseInt的用法。map会传递三个参数给其作为参数的函数,为(element...
D67 485. Max Consecutive Ones 题目链接 485. Max Consecutive Ones 题目分析 给定一个二进制数组(只含有0和1的数组),返回最长的1串。 思路 逐个遍历,若为1则计数。遇到0则判断当前计数是否大于之前记录的最大数字,并置零。 返回...
Max Consecutive Ones 题目链接:https://leetcode.com/problems... public class Solution { public int findMaxConsecutiveOnes(int[] nums) { // loop invariant: // global is the max so far, ...
..._sym], results) # 测试 x = np.eye(2, dtype=theano.config.floatX) w = np.ones((2, 2), dtype=theano.config.floatX) b = np.ones((2), dtype=theano.config.floatX) b[1] = 2 compute_elementwise(x, w, b) #...
...import cv2 import numpy as np img = cv2.imread(img7.png,0) kernel = np.ones((5,5),np.uint8) erosion = cv2.erode(img,kernel,iterations = 1) cv2.imshow(src,img) cv2.imshow(show,erosion) cv2.waitKe...
... Java 注释。 Java: class Solution{ public int findMaxConsecutiveOnes(int[] nums) { int temp=0,count=0;//temp记录当前连续1的个数,count记录当前最大连续1的个数 for (int i=0;i int: count=temp=0 ...
...1最后应该全是0。 public int singleNumber(int[] A) { int ones = 0, twos = 0; for(int i = 0; i < A.length; i++){ ones = (ones ^ A[i]) & ~twos; twos = (twos ^ A[i]...
... Java 注释。 Java: class Solution{ public int findMaxConsecutiveOnes(int[] nums) { int temp=0,count=0;//temp记录当前连续1的个数,count记录当前最大连续1的个数 for (int i=0;i int: count=temp=0 ...
...it efficiently? Solution class Solution { public int findMaxConsecutiveOnes(int[] nums) { int max = 0, lastZeroIndex = -1; int l = 0, r = 0; while (r < nums.length) { ...
... Java 注释。 Java: class Solution{ public int findMaxConsecutiveOnes(int[] nums) { int temp=0,count=0;//temp记录当前连续1的个数,count记录当前最大连续1的个数 for (int i=0;i int: count=temp=0 ...
...{ const bits = new Array(n + 1).fill(0); for (let i = 0; i { let ones = 0; while (x > 0) { x &= (x - 1); ones++; } return ones;}Java:class Solution { public int[...
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