回答:看报错是 grafana 用户名或密码错误2022-09-1516:01:56[AsyncTask]org.springframework.web.client.HttpClientErrorException$Unauthorized: 401Unauthorized:[{message:Invalidusernameorpassword}] ... atcn.ucloud.udp.utils....
问题描述:[hadoop@usdp01 ~]$ hbase shellSLF4J: Class path contains multiple SLF4J bindings.SLF4J: Found binding in [jar:file:/opt/usdp-srv/srv/udp/2.0.0.0/hdfs/share/hadoop/common/lib/slf4j-log4j12-1.7.25.jar!/org/slf4j/impl/StaticLoggerBinder.class]...
回答:看报错是访问 grafana 报错 用户名或密码错误2022-09-2611:05:03[AsyncTask]org.springframework.web.client.HttpClientErrorException$Unauthorized:401Unauthorized:[{message:Invalidusernameorpassword}] ... atcn.ucloud.udp.ut...
问题描述:2022-10-21 17:26:57`SEVERE`io.prometheus.jmx.shaded.io.prometheus.jmx.JmxCollector`io.prometheus.jmx.shaded.io.prometheus.jmx.JmxCollector collect`JMX scrape failed: java.io.IOException: Failed to retrieve RMIServer stub: javax.naming.NoIni...
问题描述:[udp-717] ERROR cn.ucloud.udp.async.task.AbstractTask - 2022-11-15 15:56:00 [AsyncTask] java.lang.IllegalStateException: No thread-bound request found: Are you referring to request attributes outside of an actual web request, or processing ...
问题描述:usdp部署安装Prometheus失败,执行失败的安装任务如下:[失败] [node129]通过 Restful 重载 Prometheus 配置文件日志报错信息如下:2023-03-22 10:42:31 [AsyncTask] Task Started: [node129]通过 Restful 重载 Prometheus 配置文件TaskInfo:[ hostname: node...
...,如此while循环反复。 class Solution(object): def isNStraightHand(self, hand, W): # c = collections.Counter(hand) hand.sort() print(hand) while hand: try: ...
...创造一个人,天生自带人手 class People: def __init__(self, hand = None): self.name = 人手 if hand is not None: self.execute = types.MethodType(hand, self) def execute(self...
...fromskimageimportmeasure,data,color #生成二值测试图像 hand=np.array([[1.64516129,1.16145833], [1.64516129,1.59375], [1.35080645,1.921875], [1.375,2.18229167], [1.68548387,1.9375], [1.60887097...
Problem Alice has a hand of cards, given as an array of integers. Now she wants to rearrange the cards into groups so that each group is size W, and consists of W consecutive cards. Return true if and...
...以下是带有__str__()和__repr__()方法的简单集合: pythonclass Hand: def __init__(self, dealer_card, *cards): self.dealer_card = dealer_card self.cards = list(cards) def __str__(self): ...
... position: relative; overflow: hidden; z-index: 1; } .animate-hand{ height: 134px; width: 134px; display: block; position: absolute; background: currentColor; o...
... position: relative; overflow: hidden; z-index: 1; } .animate-hand{ height: 134px; width: 134px; display: block; position: absolute; background: currentColor; o...
...pture =cv2.VideoCapture(0,cv2.CAP_DSHOW)# 初始化(模型使用之前)mpHands =mp.solutions.handshands=mpHands.Hands()mpDraw=mp.solutions.drawing_utilspTime=0cTime=0# 循环显示帧while True : success, img = capture.rea...
...是不可变对象。这种风格的定义更适合有状态的对象,如Hand,它的内容总是在变化的。我们将通过第二个示例为您提供一个有状态的对象在接下来的章节。 5. 从可变手牌变为冻结手牌 如果我们想对具体的Hand实例进行统计分析...
...再分牌。有几种方法,我们可以模拟一下: 我们可以由Hand.split()方法创建一个SplitHand子类。在此我们不详细展示。 我们可以在Hand对象中创建一个状态属性,由Hand.split()方法创建。理想情况下,这是一个布尔值,但是我们可以...
...gn: center; line-height: 2; transform: translate(-50%, -50%); } .hour-hand, .minute-hand, .second-hand { position: absolute; top: 50%; left: 50%; } .hour-hand { width: 2.5%; height:...
...图像创建文字提示,可以使用 title 属性。 二、cursor:hand 在IE10下无法让光标变成手形 这个问题也比较奇怪,估计也是兼容性的问题,上网找到了一篇比较好的文章,弄明白了cursor:hand 与 cursor:pointer 的区别 cursor:hand 与 cur...
...总是为真?终究,suit在21点没有意义。 如果我们想决定Hand对象是否可以分牌,我们最好看下这两个代码片段。以下是第一个代码片段: if hand.cards[0] == hand.cards[1] 下面是第二个代码片段: if hand.cards[0].rank == hand.cards[1].rank 虽然...
ChatGPT和Sora等AI大模型应用,将AI大模型和算力需求的热度不断带上新的台阶。哪里可以获得...
大模型的训练用4090是不合适的,但推理(inference/serving)用4090不能说合适,...
图示为GPU性能排行榜,我们可以看到所有GPU的原始相关性能图表。同时根据训练、推理能力由高到低做了...