回答:以oracle为例:SELECT * FROM(SELECT A.*, ROWNUM RNFROM (SELECT rs.student_id,count(1) FROM relationship rs group by rs.student_id order by count(1) desc) AWHERE ROWNUM = 0
...和课程类 课程类 /imooc_collection_map_demo/src/com/imooc/collection/Course.java package com.imooc.collection; //课程类 public class Course { public String id; public String name; public Cour...
...AULT CHARSET=utf8; DESC `teacher`; # 创建课程表 DROP TABLE IF EXISTS `course`; CREATE TABLE `course`( `cid` INT UNSIGNED NOT NULL AUTO_INCREMENT , `cname` VARCHAR(50) NOT NULL , `teacher_id`...
运行结果: 数据库的2个表:course表 student表 ps:一定要build path导入数据库用的jar包,以及在在lib文件夹中导入数据库jar包 文件目录结构: 具体代码:index.jsp 首页 欢迎进入选课系统 欢迎进入选课 系统 学生登录 ...
运行结果: 数据库的2个表:course表 student表 ps:一定要build path导入数据库用的jar包,以及在在lib文件夹中导入数据库jar包 文件目录结构: 具体代码:index.jsp 首页 欢迎进入选课系统 欢迎进入选课 系统 学生登录 ...
...* ArrayList的增删改查 * */ public class ListTest { private List coursesList; // 备选课程列表 public ListTest() { this.coursesList = new ArrayList(); } public List getCour...
Course Schedule I There are a total of n courses you have to take, labeled from 0 to n - 1.Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is e...
...具体的实现 /** * 课程教练类 */ public class Coach { private CourseBuilder courseBuilder; public void setCourseBuilder(CourseBuilder courseBuilder) { this.courseBuilder = courseBuilder; ...
... return .format(self.name) 一对多关系现在创建第二个映射类 Course,它对应的数据表 course 存放课程数据。一个课程作者可以创建多个课程,一个课程对应唯一的课程作者,这种关系被称为一对多或者多对一关系,这是最常用的数据...
Course Schedule Problem There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, whi...
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