Problem
Given a binary search tree (BST) with duplicates, find all the mode(s) (the most frequently occurred element) in the given BST.
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than or equal to the node"s key.
The right subtree of a node contains only nodes with keys greater than or equal to the node"s key.
Both the left and right subtrees must also be binary search trees.
For example:
Given BST [1,null,2,2],
1 2 / 2
return [2].
Note: If a tree has more than one mode, you can return them in any order.
Follow up: Could you do that without using any extra space? (Assume that the implicit stack space incurred due to recursion does not count).
Solutionclass Solution { int count = 0; int maxCount = 0; Integer pre = null; public int[] findMode(TreeNode root) { ListresList = new ArrayList<>(); helper(root, resList); return resList.stream().mapToInt(i->i).toArray(); } private void helper(TreeNode root, List res) { if (root == null) return; helper(root.left, res); if (pre == null) { pre = root.val; count = 1; maxCount = 1; res.add(root.val); } else { if (root.val == pre) { count++; if (count > maxCount) { res.clear(); maxCount = count; } } else { pre = root.val; count = 1; } if (count == maxCount) { res.add(root.val); } } helper(root.right, res); } }
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