[LeetCode] 247. Strobogrammatic Number II

GHOST_349178 发布于2019-08-16 13:50 / 1349人阅读

Problem

A strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside down).

Find all strobogrammatic numbers that are of length = n.

Example:

Input: n = 2
Output: ["11","69","88","96"]

Solution

class Solution {
    public List findStrobogrammatic(int n) {
        List res = new ArrayList<>();
        if (n == 0) return res;
        if (n == 1) return Arrays.asList("0", "1", "8");
        Map map = new HashMap();
        map.put("0", "0");
        map.put("1", "1");
        map.put("6", "9");
        map.put("8", "8");
        map.put("9", "6");
        dfs(map, new char[n], 0, n, res);
        return res;
    }
    private void dfs(Map map, char[] buffer, int index, int n, List res) {
        // when index just passed the mid point, (n+1)/2 works for both odd and even
        if (index == (n+1)/2) {
            res.add(String.valueOf(buffer));
            return;
        }
        for (char ch: map.keySet()) {
            if (index == 0 && n > 1 && ch == "0") continue;
            if (index == n/2 && (ch == "6" || ch == "9")) continue;
            buffer[index] = ch;
            buffer[n-1-index] = map.get(ch);
            dfs(map, buffer, index+1, n, res);
        }
    }
}

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