Problem
Given an array of words and a width maxWidth, format the text such that each line has exactly maxWidth characters and is fully (left and right) justified.
You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces " " when necessary so that each line has exactly maxWidth characters.
Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.
For the last line of text, it should be left justified and no extra space is inserted between words.
Note:
A word is defined as a character sequence consisting of non-space characters only.
Each word"s length is guaranteed to be greater than 0 and not exceed maxWidth.
The input array words contains at least one word.
Example 1:
Input: words = ["This", "is", "an", "example", "of", "text", "justification."] maxWidth = 16 Output: [ "This is an", "example of text", "justification. " ]
Example 2:
Input: words = ["What","must","be","acknowledgment","shall","be"] maxWidth = 16 Output: [ "What must be", "acknowledgment ", "shall be " ] Explanation: Note that the last line is "shall be " instead of "shall be", because the last line must be left-justified instead of fully-justified. Note that the second line is also left-justified becase it contains only one word.
Example 3:
Input: words = ["Science","is","what","we","understand","well","enough","to","explain", "to","a","computer.","Art","is","everything","else","we","do"] maxWidth = 20 Output: [ "Science is what we", "understand well", "enough to explain to", "a computer. Art is", "everything else we", "do " ]Solution
class Solution { public ListfullJustify(String[] words, int n) { List res = new ArrayList<>(); if (words == null || words.length == 0) return res; for (String word: words) { if (word.length() > n) { throw new IllegalArgumentException("Invalid input."); } } int index = 0; while (index < words.length) { int len = words[index].length(); int next = index+1; while (next < words.length) { if (len+1+words[next].length() > n) break; len += (1+words[next].length()); next++; } StringBuilder sb = new StringBuilder(); int count = next-1-index; //if reached last line, or still in same line of index if (next == words.length || count == 0) { for (int i = index; i < next; i++) { sb.append(words[i]+" "); } //delete the last extra space sb.deleteCharAt(sb.length()-1); //fill the total length to n with white space for (int i = sb.length(); i < n; i++) { sb.append(" "); } } else { int spaces = (n-len)/count; int remains = (n-len)%count; for (int i = index; i < next; i++) { sb.append(words[i]); if (i < next-1) { for (int j = 0; j <= (spaces+((i-index) < remains ? 1 : 0)); j++) { sb.append(" "); } } } } res.add(sb.toString()); index = next; } return res; } }
文章版权归作者所有,未经允许请勿转载,若此文章存在违规行为,您可以联系管理员删除。
转载请注明本文地址:https://www.ucloud.cn/yun/72275.html
68. Text JustificationDescriptionHintsSubmissionsDiscussSolutionGiven an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justi...
摘要:题目链接题目分析给定一个整数数组,将值为的元素移动到数组末尾,而不改动其他元素出现的顺序。再在去后的元素末尾填充到计算出的数组长度。最终代码若觉得本文章对你有用,欢迎用爱发电资助。 D68 283. Move Zeroes 题目链接 283. Move Zeroes 题目分析 给定一个整数数组,将值为0的元素移动到数组末尾,而不改动其他元素出现的顺序。 思路 计算总共有多少个元素。 再...
摘要:题目罗马数字包含以下七种字符,,,,,和。字符数值例如,罗马数字写做,即为两个并列的。通常情况下,罗马数字中小的数字在大的数字的右边。同样地,数字表示为。给定一个罗马数字,将其转换成整数。 [TOC] 题目 罗马数字包含以下七种字符: I, V, X, L,C,D 和 M。 字符 数值 I 1 V 5 X ...
摘要:题目例子我的解法其他解法这个方法不用转化成字符串,直接得到的数再除 1. 题目 A self-dividing number is a number that is divisible by every digit it contains. For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 ...
1 題目 There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up at (0, 0) after it completes its moves. The move sequence is re...
阅读 2847·2021-09-22 15:54
阅读 1869·2019-08-30 15:53
阅读 2207·2019-08-29 16:33
阅读 1401·2019-08-29 12:29
阅读 1367·2019-08-26 11:41
阅读 2344·2019-08-26 11:34
阅读 2922·2019-08-23 16:12
阅读 1400·2019-08-23 15:56