[LeetCode] 448. Find All Numbers Disappeared in an

Scorpion 发布于2019-08-16 13:39 / 797人阅读

Problem

Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once.

Find all the elements of [1, n] inclusive that do not appear in this array.

Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space.

Example:

Input:
[4,3,2,7,8,2,3,1]

Output:
[5,6]

Solution

class Solution {
    public List findDisappearedNumbers(int[] nums) {
        List res = new ArrayList<>();
        for (int i = 0; i < nums.length; i++) {
            int val = Math.abs(nums[i])-1;
            if (nums[val] > 0) nums[val] = -nums[val];
        }
        for (int i = 0; i < nums.length; i++) {
            if (nums[i] > 0) res.add(i+1);
        }
        return res;
    }
}

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