[LintCode] The Number In Words

姘存按发布于2019-08-16 12:40 / 1161人阅读

Problem

Given a non-negative integer n, print the number in words.

Example

Given n = 125

Return one hundred twenty five

Solution

class Solution {
    private String[] belowTen = new String[] {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};
    private String[] tenToTwenty = new String[] {"Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
    private String[] tens = new String[] {"", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
    
    public String convertWords(int num) {
        if (num == 0) return "zero";
        return helper(num);
    }
    
    private String helper(int num) {
        String result;
        if (num < 10) result = belowTen[num];
        else if (num < 20) result = tenToTwenty[num-10];
        else if (num < 100) result = tens[num/10] + " " + belowTen[num%10];
        else if (num < 1000) result = belowTen[num/100] + " Hundred " + helper(num%100);
        else if (num < 10000) result = belowTen[num/1000] + " Thousand " + helper(num%1000);
        else if (num < 1000000) result = helper(num/1000) + " Thousand " + helper(num%1000);
        else if (num < 1000000000) result = helper(num/1000000) + " Million " + helper(num%1000000);
        else result = helper(num/1000000000) + " Billion " + helper(num%1000000000);
        return result.trim().toLowerCase();
    }
}

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