Problem
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target.
ExampleExample 1:
Input:
5 / 3 6 / 2 4 7
Target = 9
Output: True
Example 2:
Input:
5 / 3 6 / 2 4 7
Target = 28
Output: False
Solution/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public boolean findTarget(TreeNode root, int k) { Queuequeue = new LinkedList (); Set set = new HashSet<>(); queue.offer(root); while (!queue.isEmpty()) { TreeNode cur = queue.poll(); if (set.contains(k-cur.val)) return true; set.add(cur.val); if (cur.left != null) queue.offer(cur.left); if (cur.right != null) queue.offer(cur.right); } return false; } }
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摘要:思路思路遍历的时候,先把节点存起来,并且与每一个值相加,判断是否等于所需值。用函数判断与所求数字之差是否在数组内。否则,遍历子节点。最终代码若觉得本文章对你有用,欢迎用爱发电资助。 D89 653. Two Sum IV - Input is a BST 题目链接 653. Two Sum IV - Input is a BST 题目分析 给定一个二叉树以及一个目标数字,判断能不能通过...
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