Problem
Given some points and a point origin in two dimensional space, find k points out of the some points which are nearest to origin.
Return these points sorted by distance, if they are same with distance, sorted by x-axis, otherwise sorted by y-axis.
Given points = [[4,6],[4,7],[4,4],[2,5],[1,1]], origin = [0, 0], k = 3
return [[1,1],[2,5],[4,4]]
/** * Definition for a point. * class Point { * int x; * int y; * Point() { x = 0; y = 0; } * Point(int a, int b) { x = a; y = b; } * } */ public class Solution { /* * @param points: a list of points * @param origin: a point * @param k: An integer * @return: the k closest points */ public Point[] kClosest(Point[] points, Point origin, int k) { ComparatorpointComparator = new Comparator () { public int compare(Point A, Point B) { if (distance(B, origin) == distance(A, origin)) { if (A.x == B.x) { return A.y - B.y; } else { return A.x - B.x; } } else { //maintain a min heap return distance(A, origin) > distance(B, origin) ? 1 : -1; } } }; PriorityQueue Q = new PriorityQueue (k, pointComparator); for (Point point: points) { Q.add(point); } Point[] res = new Point[k]; for (int i = 0; i < k; i++) { res[i] = Q.poll(); } return res; } public double distance(Point A, Point B) { int l = Math.abs(A.x - B.x); int w = Math.abs(A.y - B.y); return Math.sqrt(Math.pow(l, 2) + Math.pow(w, 2)); } }
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