378. Kth Smallest Element in a Sorted Matrix

makeFoxPlay 发布于2019-08-14 18:13 / 2253人阅读

Given a n x n matrix where each of the rows and columns are sorted in ascending order, find the kth smallest element in the matrix.
Note that it is the kth smallest element in the sorted order, not the kth distinct element.

matrix = [
   [ 1,  5,  9],
   [10, 11, 13],
   [12, 13, 15]
],
k = 8,

return 13

public class Solution {
    public int kthSmallest(int[][] matrix, int k) {
        PriorityQueue pq = new PriorityQueue<>(new Comparator(){
            public int compare(int[] a, int[] b){
                return a[2] - b[2];
            }
        });
        
        int n = matrix.length;
        // add first row
        for(int i=0; i< n; i++){
            pq.offer(new int[]{0, i, matrix[0][i]});
        }
        
        for(int i=0; i
public class Solution {
    public int kthSmallest(int[][] matrix, int k) {
        int m = matrix.length, n = matrix[0].length;
        int lo = matrix[0][0],  hi = matrix[m-1][n-1];
        while(lo < hi){
            int mid = lo + (hi-lo)/2;
            int count = 0, j = n -1;
            for(int i=0; i=0 && matrix[i][j] > mid) j--;
                // count those <= mid
                count += j+1;
            }
            // if count < k, the number is smaller
            if(count < k) lo = mid+1;
            else hi = mid;
        }
        return lo;
    }

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