摘要:记一种简单的的做法先讨论边界,若为最大值,返回然后对整数分奇偶两种情况讨论,偶数除以,奇数判断是否后能被整除且不等于,若如此则,否则每次操作后计数器,循环结束后返回计数器值。
Problem
Given a positive integer n and you can do operations as follow:
If n is even, replace n with n/2.
If n is odd, you can replace n with either n + 1 or n - 1.
What is the minimum number of replacements needed for n to become 1?
Example 1:
Input:
8
Output:
3
Explanation:
8 -> 4 -> 2 -> 1
Example 2:
Input:
7
Output:
4
Explanation:
7 -> 8 -> 4 -> 2 -> 1
or
7 -> 6 -> 3 -> 2 -> 1
记一种简单的iteration的做法:
先讨论边界case,若n为Integer最大值,返回32.
然后对整数n分奇偶两种情况讨论,偶数除以2,奇数判断是否+1后能被4整除且n不等于3,若如此则+1,否则-1. 每次操作后计数器+1,循环结束后返回计数器值。
public class Solution { public int integerReplacement(int n) { if (n == Integer.MAX_VALUE) return 32; int count = 0; while (n != 1) { if (n%2 == 0) n/=2; else { if ((n+1)%4==0 && n!=3) n+=1; else n-=1; } count++; } return count; } }
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