leetcode-78-Subsets

摘要：描述解释就是普通的动态规划吧，找准规律，所有数字过一遍，每个数字都有添加和不被添加两种情况，所有情况的综合

描述

Given a set of distinct integers, nums, return all possible subsets
(the power set).

Note:

The solution set must not contain duplicate subsets.

For example,

If nums = [1,2,3], a solution is:
[   [3],   [1],   [2],   [1,2,3],   [1,3],   [2,3],   [1,2],   [] ]

class Solution:
    def subsets(self, nums):
        """
        :type nums: List[int]
        :rtype: List[List[int]]
        """
        cur_array=[[],]
        for num in nums:
            self.dfs(cur_array,num)
        # print(cur_array)
        return cur_array

    def dfs(self,cur_array,num_in):
        # new_array1=cur_array.append(num_in)
        # new_array2=cur_array
        # print(num_in)
        new_array=list(map(lambda x:x+[num_in],cur_array))
        # print(list(new_array))
        cur_array.extend(new_array)


if __name__=="__main__":
    st=Solution()
    st.subsets([1,2,3])

解释：就是普通的动态规划吧，找准规律，所有数字过一遍，每个数字都有添加和不被添加两种情况，所有情况的综合