摘要：刷题继续昨天和大家分享了题，今天继续来刷题解法一解法一解法二解法一解法一解法一解法一解法二解法一解法二解法一解法二解法三解法一解法一解法二源代码下载这十道题的代码在我的上，如果大家想看一下每道题的输出结果，可以点击以下链接下载题我的运
刷题继续
昨天和大家分享了71-80题，今天继续来刷81~90题
Question 81:
By using list comprehension, please write a program to print the list after removing numbers which are divisible by 5 and 7 in [12,24,35,70,88,120,155].
解法一
li = [12,24,35,70,88,120,155]
li = [x for x in li if x % 35!=0]
print(li)
Question 82:
By using list comprehension, please write a program to print the list after removing the 0th, 2nd, 4th,6th numbers in [12,24,35,70,88,120,155].
解法一
li = [12,24,35,70,88,120,155]
li = [li[i] for i in range(len(li)) if i%2 != 0]
print(li)
解法二
li = [12,24,35,70,88,120,155]
li = [x for (i,x) in enumerate(li) if i%2!=0]
print(li)
Question 83:
By using list comprehension, please write a program to print the list after removing the 2nd - 4th numbers in [12,24,35,70,88,120,155].
解法一
li = [12,24,35,70,88,120,155]
li = [x for (i,x) in enumerate(li) if i<3 or 4
Question 84:
By using list comprehension, please write a program generate a 3*5*8 3D array whose each element is 0.
解法一
array = [[ [0 for col in range(8)] for col in range(5)] for row in range(3)]
print(array)
Question 85:
By using list comprehension, please write a program to print the list after removing the 0th,4th,5th numbers in [12,24,35,70,88,120,155].
解法一
li = [12,24,35,70,88,120,155]
li = [li[i] for i in range(len(li)) if i not in (0,4,5)]
print(li)
Question 86:
By using list comprehension, please write a program to print the list after removing the value 24 in [12,24,35,24,88,120,155].
解法一
li = [12,24,35,24,88,120,155]
li.remove(24)
# this will remove only the first occurrence of 24
print(li)
解法二
li = [12,24,35,24,88,120,155]
li = [x for x in li if x!=24] # Delete all 24
print(li)
Question 87:
With two given lists [1,3,6,78,35,55] and [12,24,35,24,88,120,155], write a program to make a list whose elements are intersection of the above given lists.
解法一
set1=set([1,3,6,78,35,55])
set2=set([12,24,35,24,88,120,155])
result = set1.intersection(set2)
print(result)
解法二
set1=set([1,3,6,78,35,55])
set2=set([12,24,35,24,88,120,155])
result = set1 & set2
print(result)
Question 88:
With a given list [12,24,35,24,88,120,155,88,120,155], write a program to print this list after removing all duplicate values with original order reserved.
解法一
li=[12,24,35,24,88,120,155,88,120,155]
result = set(li) #> Python 3.6 Set keep the order test
print(result)
解法二
def removeDuplicate( li ):
seen = {}
for item in li:
if item not in seen:
seen[item] = True
yield item
li = [12, 24, 35, 24, 88, 120, 155, 88, 120, 155]
ans = list(removeDuplicate(li))
print(ans)
解法三
li = [12,24,35,24,88,120,155,88,120,155]
for i in li:
if li.count(i) > 1:
li.remove(i)
print(li)
Question 89:
Define a class Person and its two child classes: Male and Female. All classes have a method "getGender" which can print "Male" for Male class and "Female" for Female class.
解法一
class Person(object):
def getGender( self ):
return "Unknown"
class Male( Person ):
def getGender( self ):
return "Male"
class Female( Person ):
def getGender( self ):
return "Female"
# Test
aMale = Male()
aFemale= Female()
print(aMale.getGender())
print (aFemale.getGender())
Question 90:
Please write a program which count and print the numbers of each character in a string input by console.*Example:
If the following string is given as input to the program:*
abcdefgabc
Then, the output of the program should be:
a,2
c,2
b,2
e,1
d,1
g,1
f,1
解法一
s=input()
dic = {word:s.count(word) for word in s}
for k, v in dic.items():
print(f"{k},{v}")
解法二
s = input()
for letter in range(ord("a"),ord("z")+1): # ord() gets the ascii value of a char
letter = chr(letter) # chr() gets the char of an ascii value
cnt = s.count(letter)
if cnt > 0:
print("{},{}".format(letter,cnt))
源代码下载
这十道题的代码在我的github上，如果大家想看一下每道题的输出结果，可以点击以下链接下载：
Python 81-90题
我的运行环境Python 3.6+,如果你用的是Python 2.7版本，绝大多数不同就体现在以下3点：
raw_input()在Python3中是input()
print需要加括号
fstring可以换成.format(),或者%s，%d
谢谢大家，我们下期见！希望各位朋友不要吝啬，把每道题的更高效的解法写在评论里，我们一起进步！！！
