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Python基础练习100题 ( 1~ 10)

Java3y / 3170人阅读

摘要:一套全面的练习,大家智慧的结晶大家好,好久不见,我最近在上发现了一个好东西,是关于夯实基础的道题,原作者是在的时候创建的,闲来无事,非常适合像我一样的小白来练习对于每一道题,解法都不唯一,我在这里仅仅是抛砖引玉,希望可以集合大家的智慧,如果

一套全面的练习,大家智慧的结晶

大家好,好久不见,我最近在Github上发现了一个好东西,是关于夯实Python基础的100道题,原作者是在Python2的时候创建的,闲来无事,非常适合像我一样的小白来练习

对于每一道题,解法都不唯一,我在这里仅仅是抛砖引玉,希望可以集合大家的智慧,如果哪道题有其他解法,希望可以在评论中留下大家宝贵的意见!每次我会更新10道题,一共会更新10篇,这也算是对我之前的文章一个总结啦,如果没有看到我之前有关Python的小白学习分享的同学们,可以戳下面连接查看哈:

Python 基础起步,写给同为小白的你

Python 进阶之路

Python Pandas 之旅

如果大家想要和我联系,可以访问我的个人主页:

我的个人主页

好啦,闲话少说,让我们开始今天的刷题之旅吧!

Question 1:
Write a program which will find all such numbers which are divisible by 7 but are not a multiple of 5,between 2000 and 3200 (both included).The numbers obtained should be printed in a comma-separated sequence on a single line.
解法一
for i in range(2000,3201):
    if i%7 == 0 and i%5!=0:
        print(i,end=",")
print("")
解法二
numbers = [str(x) for x in range(2000,3201) if (x%7==0) and (x%5!=0)]
print (",".join(numbers))
Question 2:
*Write a program which can compute the factorial of a given numbers.The results should be printed in a comma-separated sequence on a single line.Suppose the following input is supplied to the program: 8
Then, the output should be:40320*
解法一
def fact(x):
    if x == 0:
        return 1
    return x * fact(x - 1)
x=int(input())
print(fact(x))
解法二
import math as ma
x=int(input())
print(ma.factorial(x))
解法三
from functools import reduce
from operator import mul

x=int(input())
print(reduce(mul,range(1,x+1)))
Question 3:
With a given integral number n, write a program to generate a dictionary that contains (i, i x i) such that is an integral number between 1 and n (both included). and then the program should print the dictionary.Suppose the following input is supplied to the program: 8

Then, the output should be:

{1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64}

解法一
n=int(input())
d=dict()
for i in range(1,n+1):
    d[i]=i*i
print(d)

解法二
n=int(input())
d={x:x*x for x in range(1,n+1)}
print(d)
Question 4:
Write a program which accepts a sequence of comma-separated numbers from console and generate a list and a tuple which contains every number.Suppose the following input is supplied to the program:
34,67,55,33,12,98
Then, the output should be:
["34", "67", "55", "33", "12", "98"]
("34", "67", "55", "33", "12", "98")

解法一
values=input()
l=values.split(",")
t=tuple(l)
print(f"List of values : {l}")
print(f"Tuple of values : {t}")

Question 5:

Define a class which has at least two methods:

getString: to get a string from console input

printString: to print the string in upper case.

Also please include simple test function to test the class methods.


解法一
class InputOutString:
    def __init__(self):
        self.s = ""

    def getString(self):
        self.s = input()

    def printString(self):
        print(self.s.upper())
        
# Test

a = InputOutString()
a.getString()
a.printString()
Question 6:
Write a program that calculates and prints the value according to the given formula:

Q = Square root of [(2 C D)/H]

Following are the fixed values of C and H:

C is 50. H is 30.

D is the variable whose values should be input to your program in a comma-separated sequence.For example
Let us assume the following comma separated input sequence is given to the program:*

100,150,180
The output of the program should be:
18,22,24

解法一
import math
c=50
h=30
value = []
items= [x for x in input("Input numbers comma-separated:").split(",")]
for d in items:
    value.append(str(int(round(math.sqrt(2*c*float(d)/h)))))

print (",".join(value))
Question 7:
Write a program which takes 2 digits, X,Y as input and generates a 2-dimensional array. The element value in the i-th row and j-th column of the array should be i * j.

Note: i=0,1.., X-1; j=0,1,¡­Y-1. Suppose the following inputs are given to the program: 3,5

Then, the output of the program should be:

[[0, 0, 0, 0, 0], [0, 1, 2, 3, 4], [0, 2, 4, 6, 8]]

解法一
x,y = map(int,input().split(","))
lst = []

for i in range(x):
    tmp = []
    for j in range(y):     
        tmp.append(i*j)
    lst.append(tmp)
    
print(lst)

解法二
x,y = map(int,input().split(","))
lst = [[i*j for j in range(y)] for i in range(x)]  
print(lst)
Question 8:
Write a program that accepts a comma separated sequence of words as input and prints the words in a comma-separated sequence after sorting them alphabetically.

Suppose the following input is supplied to the program:

without,hello,bag,world
Then, the output should be:
bag,hello,without,world

解法一
original_string = input("Input Text:")
l = original_string.split(",")
final_string = sorted(l,key=str)
print(",".join(final_string))
解法二
lst = input().split(",")
lst.sort()
print(",".join(lst))
Question 9:
Write a program that accepts sequence of lines as input and prints the lines after making all characters in the sentence capitalized.

Suppose the following input is supplied to the program:

Hello world
Practice makes perfect
Then, the output should be:
HELLO WORLD
PRACTICE MAKES PERFECT

解法一
lines = []
while True:
    s = input()
    if s:
        lines.append(s.upper())  
    else:
        break;

for sentence in lines:
    print(sentence)
Question 10:
Write a program that accepts a sequence of whitespace separated words as input and prints the words after removing all duplicate words and sorting them alphanumerically.

Suppose the following input is supplied to the program:

hello world and practice makes perfect and hello world again
Then, the output should be:
again and hello makes perfect practice world

解法一
word = input().split()

for i in word:
    if word.count(i) > 1:    #count function returns total repeatation of an element that is send as argument
        word.remove(i)     # removes exactly one element per call

word.sort()
print(" ".join(word))

解法二

s = input("Input Text:")
words = [word for word in s.split(" ")]
print (" ".join(sorted(list(set(words)))))
源代码下载

我把前十道题的代码上传到github上啦,如果大家想看一下每道题的输出结果,可以点击以下链接下载:

Python 1-10题

我的运行环境Python 3.6+,如果你用的是Python 2.7版本,绝大多数不同就体现在以下3点:

raw_input()在Python3中是input()

print需要加括号

fstring 可以换成.format(), 或者%s,%d

谢谢大家,我们下期见!希望各位朋友不要吝啬,把每道题的更高效的解法写在评论里,我们一起进步!!!

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