Python抓取歌词自制FreeStyle

摘要：故事的起因是上周六看中国好声音一个周杰伦战队的学员用人工智能写的歌词，于是乎，我也有了这个想法，代码的主题思路是看先生的文章，虽然最后不能写出一首歌，但是押韵脚这事情分分钟搞定了主题的思路，就是先抓取很多首歌曲的歌词，利用分词后，将分好的词

故事的起因是上周六看《中国好声音》,一个周杰伦战队的学员用人工智能写的歌词，于是乎，我也有了这个想法，代码的主题思路是看Crossin先生的文章，虽然最后不能写出一首歌，但是押韵脚这事情分分钟搞定了

主题的思路，就是先抓取很多首歌曲的歌词，利用jieba分词后，将分好的词按照押韵表进行分类，最后匹配查询就可以了

这个地方可以去网上搜押韵表

#引用各种需要的库
import requests
import jieba
import re
from xpinyin import Pinyin
p = Pinyin()

RhymeIndex = [("1", ["a", "ia", "ua"]), ("2", ["ai", "uai"]), ("3", ["an", "ian", "uan"]),
              ("4", ["ang", "iang", "uang"]), ("5", ["ao", "iao"]), ("6", ["e", "o", "uo"]), ("7", ["ei", "ui"]),
              ("8", ["en", "in", "un"]), ("9", ["eng", "ing", "ong", "iong"]), ("10", ["er"]), ("11", ["i"]),
              ("12", ["ie", "ye"]), ("13", ["ou", "iu"]), ("14", ["u"]), ("16", ["ue"]), ("15", ["qu", "xu", "yu"])]

RhymeDct = {"ui": "7", "uan": "3", "ian": "3", "iu": "13", "en": "8", "ue": "16", "ing": "9", "a": "1", "ei": "7",
            "eng": "9", "uo": "6", "ye": "12", "in": "8", "ou": "13", "ao": "5", "uang": "4", "ong": "9", "ang": "4",
            "ai": "2", "ua": "1", "uai": "2", "an": "3", "iao": "5", "ia": "1", "ie": "12", "iong": "9", "i": "11",
            "er": "10", "e": "6", "u": "14", "un": "8", "iang": "4", "o": "6", "qu": "15", "xu": "15", "yu": "15"}

分好的词与押韵表对应起来，举个栗子，比如“没有”对应的是“7-13”，就等于你给每个词都贴了一个标签，这样你以后想搜索的时候，就可以根据标签找到这些词了

def _analysis_words(words):
        word_py =p.get_pinyin((u"{}".format(words)))
        lst_words = word_py.split("-")
        r = []
        for i in lst_words:
            while True:
                if not i:
                    break
                token = RhymeDct.get(i, None)
                if token:
                    r.append(token)
                    break
                i = i[1:]
        if len(r) == len(words):
            return "-".join(r)
# print(_analysis_words("兄弟"))

这个地方数据爬取的越多，肯定你的词库就越壮大，后面分词也越高，我这里只爬取了3首歌曲的歌词，并且最后是存储到txt中，当然，放数据库里就更好了

def GetKeyword():
    #歌曲列表
    # url = "http://music.163.com/api/playlist/detail?id=808976784"
    # req = requests.get(url)
    # data = req.json()
    # print(data["result"]["tracks"] )
    # tracks =data["result"]["tracks"]  #歌曲列表
    tracks=["431795900","33850315","430053482"]
    #写入记事本文件
    with open("keyword.txt","a") as f:
        f.write("[")
        for i in tracks:
            print(111)
            #歌词
            # lrcurl = "http://music.163.com/api/song/lyric?os=pc&id="+str(i["id"])+"&lv=-1&kv=-1&tv=-1"
            lrcurl = "http://music.163.com/api/song/lyric?os=pc&id="+str(i)+"&lv=-1&kv=-1&tv=-1"
            lrcreq = requests.get(lrcurl)
            dt = lrcreq.json()
            lrc=re.sub(u"[.*?]", "", dt["lrc"]["lyric"])
            #jieba分词
            seg_list = list(jieba.cut(lrc, cut_all=True))
            for i in seg_list:
                #加入判断，只写入2个字组成的词
                if len(i)==2:
                    #写入格式：{"7-13":"追求"}
                    if _analysis_words(i)!=None:
                        f.write("{""+_analysis_words(i)+"":""+i+""},")
        f.write("]")
        f.close()
       

GetKeyword()

def Findkey(str):
    result={}
    with open("keyword.txt", "r") as f:
        # print(f.readlines())
        list=eval(f.readlines()[0])
        for item in list:
            if item.get(str):
                key=item.get(str)
                number=result.get(key)
                #如果一个词出现多次，进行次数累加，用来表示频次
                if number !=None and number>=1:
                    result[key]=number+1
                else:
                    result.update({key:1})
        f.close()
        print(result) 

key=input("请输入关键词:")
str=_analysis_words(key)
print("匹配押韵的词：")
Findkey(str)

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