资讯专栏INFORMATION COLUMN

Mysql 常用SQL语句集锦

asoren / 662人阅读

摘要:基础篇查询时间,友好提示时间戳类型一个返回多个总数同上。根据上面的数据,应该得到的范围。

基础篇

//查询时间,友好提示
$sql = "select date_format(create_time, "%Y-%m-%d") as day from table_name";
//int 时间戳类型
$sql = "select from_unixtime(create_time, "%Y-%m-%d") as day from table_name";
//一个sql返回多个总数
$sql = "select count(*) all, " ;
$sql .= " count(case when status = 1 then status end) status_1_num, ";
$sql .= " count(case when status = 2 then status end) status_2_num ";
$sql .= " from table_name";
//Update Join / Delete Join
$sql = "update table_name_1 ";
$sql .= " inner join table_name_2 on table_name_1.id = table_name_2.uid ";
$sql .= " inner join table_name_3 on table_name_3.id = table_name_1.tid ";
$sql .= " set *** = *** ";
$sql .= " where *** ";

//delete join 同上。
//替换某字段的内容的语句
$sql = "update table_name set content = REPLACE(content, "aaa", "bbb") ";
$sql .= " where (content like "%aaa%")";
//获取表中某字段包含某字符串的数据
$sql = "SELECT * FROM `表名` WHERE LOCATE("关键字", 字段名) ";
//获取字段中的前4位
$sql = "SELECT SUBSTRING(字段名,1,4) FROM 表名 ";
//查找表中多余的重复记录
//单个字段
$sql = "select * from 表名 where 字段名 in ";
$sql .= "(select 字段名 from 表名 group by 字段名 having count(字段名) > 1 )";
//多个字段
$sql = "select * from 表名 别名 where (别名.字段1,别名.字段2) in ";
$sql .= "(select 字段1,字段2 from 表名 group by 字段1,字段2 having count(*) > 1 )";
//删除表中多余的重复记录(留id最小)
//单个字段
$sql = "delete from 表名 where 字段名 in ";
$sql .= "(select 字段名 from 表名 group by 字段名 having count(字段名) > 1)  ";
$sql .= "and 主键ID not in ";
$sql .= "(select min(主键ID) from 表名 group by 字段名 having count(字段名 )>1) ";
//多个字段
$sql = "delete from 表名 别名 where (别名.字段1,别名.字段2) in ";
$sql .= "(select 字段1,字段2 from 表名 group by 字段1,字段2 having count(*) > 1) ";
$sql .= "and 主键ID not in ";
$sql .= "(select min(主键ID) from 表名 group by 字段1,字段2 having count(*)>1) ";

业务篇

连续范围问题

//创建测试表
CREATE TABLE `test_number` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `number` int(11) unsigned NOT NULL DEFAULT "0" COMMENT "数字",
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
//创建测试数据
insert into test_number values(1,1);
insert into test_number values(2,2);
insert into test_number values(3,3);
insert into test_number values(4,5);
insert into test_number values(5,7);
insert into test_number values(6,8);
insert into test_number values(7,10);
insert into test_number values(8,11);

实验目标:求数字的连续范围。

根据上面的数据,应该得到的范围。

1-3
5-5
7-8
10-11
//执行Sql
select min(number) start_range,max(number) end_range
from
(
    select number,rn,number-rn diff from
    (
        select number,@number:=@number+1 rn from test_number,(select @number:=0) as number
    ) b
) c group by diff;

签到问题

//创建参考表(模拟数据需要用到)
CREATE TABLE `test_nums` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT="参考表";
//模拟数据,插入 1-10000 连续数据.
//创建测试表
CREATE TABLE `test_sign_history` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `uid` int(11) unsigned NOT NULL DEFAULT "0" COMMENT "用户ID",
  `create_time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP COMMENT "签到时间",
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT="签到历史表";
//创建测试数据
insert into test_sign_history(uid,create_time)
select ceil(rand()*10000),str_to_date("2016-12-11","%Y-%m-%d")+interval ceil(rand()*10000) minute
from test_nums where id<31;
//统计每天的每小时用户签到情况
select
    h,
    sum(case when create_time="2016-12-11" then c else 0 end) 11Sign,
    sum(case when create_time="2016-12-12" then c else 0 end) 12Sign,
    sum(case when create_time="2016-12-13" then c else 0 end) 13Sign,
    sum(case when create_time="2016-12-14" then c else 0 end) 14Sign,
    sum(case when create_time="2016-12-15" then c else 0 end) 15Sign,
    sum(case when create_time="2016-12-16" then c else 0 end) 16Sign,
    sum(case when create_time="2016-12-17" then c else 0 end) 17Sign
from
(
    select
        date_format(create_time,"%Y-%m-%d") create_time,
        hour(create_time) h,
        count(*) c
    from test_sign_history
    group by
        date_format(create_time,"%Y-%m-%d"),
        hour(create_time)
) a
group by h with rollup;

//统计每天的每小时用户签到情况(当某个小时没有数据时,显示0)
select
    h ,
    sum(case when create_time="2016-12-11" then c else 0 end) 11Sign,
    sum(case when create_time="2016-12-12" then c else 0 end) 12Sign,
    sum(case when create_time="2016-12-13" then c else 0 end) 13Sign,
    sum(case when create_time="2016-12-14" then c else 0 end) 14Sign,
    sum(case when create_time="2016-12-15" then c else 0 end) 15Sign,
    sum(case when create_time="2016-12-16" then c else 0 end) 16Sign,
    sum(case when create_time="2016-12-17" then c else 0 end) 17Sign
from
(
    select b.h h,c.create_time,c.c from
     (
        select id-1 h from test_nums where id<=24
     ) b
     left join
     (
        select
         date_format(create_time,"%Y-%m-%d") create_time,
         hour(create_time) h,
         count(*) c
        from test_sign_history
        group by
         date_format(create_time,"%Y-%m-%d"),
         hour(create_time)
      ) c on (b.h=c.h)
) a
group by h with rollup;

//统计每天的用户签到数据和每天的增量数据
select
        type,
        sum(case when create_time="2016-12-11" then c else 0 end) 11Sign,
        sum(case when create_time="2016-12-12" then c else 0 end) 12Sign,
        sum(case when create_time="2016-12-13" then c else 0 end) 13Sign,
        sum(case when create_time="2016-12-14" then c else 0 end) 14Sign,
        sum(case when create_time="2016-12-15" then c else 0 end) 15Sign,
        sum(case when create_time="2016-12-16" then c else 0 end) 16Sign,
        sum(case when create_time="2016-12-17" then c else 0 end) 17Sign
from
(
        select b.create_time,ifnull(b.c-c.c,0) c,"Increment" type from
        (
            select
             date_format(create_time,"%Y-%m-%d") create_time,
             count(*) c
            from test_sign_history
            group by
             date_format(create_time,"%Y-%m-%d")
        ) b
        left join
        (
            select
             date_format(create_time,"%Y-%m-%d") create_time,
             count(*) c
            from test_sign_history
            group by
             date_format(create_time,"%Y-%m-%d")
        ) c on(b.create_time=c.create_time+ interval 1 day)
    union all
        select
         date_format(create_time,"%Y-%m-%d") create_time,
         count(*) c,
         "Current"
        from test_sign_history
        group by
         date_format(create_time,"%Y-%m-%d")
) a
group by type
order by case when type="Current" then 1 else 0 end desc;

//模拟不同的用户签到了不同的天数
insert into test_sign_history(uid,create_time)
select uid,create_time + interval ceil(rand()*10) day from test_sign_history,test_nums
where test_nums.id <10 order by rand() limit 150;
//统计签到天数相同的用户数量
select
    sum(case when day=1 then cn else 0 end) 1Day,
    sum(case when day=2 then cn else 0 end) 2Day,
    sum(case when day=3 then cn else 0 end) 3Day,
    sum(case when day=4 then cn else 0 end) 4Day,
    sum(case when day=5 then cn else 0 end) 5Day,
    sum(case when day=6 then cn else 0 end) 6Day,
    sum(case when day=7 then cn else 0 end) 7Day,
    sum(case when day=8 then cn else 0 end) 8Day,
    sum(case when day=9 then cn else 0 end) 9Day,
    sum(case when day=10 then cn else 0 end) 10Day
from
(
    select c day,count(*) cn
    from
    (
        select uid,count(*) c from test_sign_history group by uid
    ) a
    group by c
) b;

//统计每个用户的连续签到时间
select * from (
    select d.*,
    @ggid := @cggid,
    @cggid := d.uid,
    if(@ggid = @cggid, @grank := @grank + 1, @grank := 1) grank
    from
    (
        select uid,min(c.create_time) begin_date ,max(c.create_time) end_date,count(*) count from
        (
            select
            b.*,
            @gid := @cgid,
            @cgid := b.uid,
            if(@gid = @cgid, @rank := @rank + 1, @rank := 1) rank,
            b.diff-@rank flag from (
                select
                distinct
                uid,
                date_format(create_time,"%Y-%m-%d") create_time,
                datediff(create_time,now()) diff
                from test_sign_history order by uid,create_time
            ) b, (SELECT @gid := 1, @cgid := 1, @rank := 1) as a
        ) c group by uid,flag
        order by uid,count(*) desc
    ) d,(SELECT @ggid := 1, @cggid := 1, @grank := 1) as e
)f
where grank=1;

如果大家需要下载上述的相关数据表,进行测试。

可以关注微信公众号,回复 “签到数据表”,即可获取数据表。


Thanks ~

文章版权归作者所有,未经允许请勿转载,若此文章存在违规行为,您可以联系管理员删除。

转载请注明本文地址:https://www.ucloud.cn/yun/22153.html

相关文章

  • Mysql 常用SQL语句集锦

    摘要:以下是工作中常用的语句查询时间,友好提示日期类型时间戳类型一个返回多个总数同上。 以下是工作中常用的SQL语句 : 查询时间,友好提示 timestamp 日期类型$sql = select date_format(create_time, %Y-%m-%d) as day from table_name; int 时间戳类型$sql = select from_unixtime(...

    bang590 评论0 收藏0

发表评论

0条评论

最新活动
阅读需要支付1元查看
<